A coil of resistance 10 ohm has a flux change of 0.05 Wb to 0.55 Wb in 0.1 sec. What is the induced current?
Answer & explanation
Correct answer: option 3
The correct answer is Option 3: 0.5A
$ \text{Induced current } I = \frac{\xi}{R} = \frac{1}{R} \frac{d\Phi}{dt} =\frac{1}{10} \frac{0.55 - 0.05}{0.1} = 0.5A$