Practicing Success
Find the perimeter of major sector of a circle of radius 12 metres, whose minor sector subtends an angle of 75° at the centre. |
24 + 5π metres 24 + 19π metres 24 - 5π metres 24 - 19π metres |
24 + 19π metres |
Formula Used Perimeter of major arc = 2 x \(\Pi \) x r x \(\theta \)/360 + 2r Where \(\theta \) = 360 - angle subtended by minor arc Calculations Here, we have radius of the circle = 12 m and minor sector angle subtends an angle = \({75}^\circ\) Angle subtended by major arc = \({360}^\circ\) - \({75}^\circ\) = \({285}^\circ\) Perimeter of major arc = 2 x \(\Pi \) x 12 x 285/360 + 2 x 12 = 19\(\Pi \) + 24 metres Therefore, Perimeter of major arc is 19\(\Pi \) + 24 metres |