In an experiment, the measured value of Δo for an octahedral complex [ML6]n+ is found to be 18000 cm-1. Calculate the value of Δt for a tetrahedral complex [ML4]n+.
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 8000 cm-1
The tetrahedral and octahedral splittings are related by:
\( \displaystyle \Delta_t=\frac{4}{9}\,\Delta_o \)
With Δo = 18000 cm−1:
\( \displaystyle \Delta_t=\frac{4}{9}\times18000\ \mathrm{cm^{-1}} \)
\( \displaystyle \Delta_t=4\times2000=8000\ \mathrm{cm^{-1}} \)
So Δt = 8000 cm−1.
NCERT (2026-27 edition):
Crystal Field Splitting in Tetrahedral Coordination Entities
