$\sin\{\cot^{-1}(\tan\,\cos^{-1}x)\}$ is equal to:
Answer & explanation
Correct answer: option 1
$\cot^{-1}\tan(\cos^{-1}x)=\frac{π}{2}-\tan^{-1}\tan(\cos^{-1}x)=\frac{π}{2}-\cos^{-1}x$
$\sin\{\cot^{-1}(\tan\,\cos^{-1}x)\}$ is equal to:
Correct answer: option 1
$\cot^{-1}\tan(\cos^{-1}x)=\frac{π}{2}-\tan^{-1}\tan(\cos^{-1}x)=\frac{π}{2}-\cos^{-1}x$