If $\omega (n)$ = Number of distinct prime factors of n, n ∈ N, then what is the value of $\omega (105)$ ?
Answer & explanation
Correct answer: option 3
The correct answer is option (3) : 3
$∵105=3×5×7$
$⇒\omega(105)=3$
If $\omega (n)$ = Number of distinct prime factors of n, n ∈ N, then what is the value of $\omega (105)$ ?
Correct answer: option 3
The correct answer is option (3) : 3
$∵105=3×5×7$
$⇒\omega(105)=3$