A number is divided into two parts in such a way that 50% of 1st part is 4 more than 40 % of 2nd part and 70% of 1st part is 2 more than 60% of the 2nd part, then the number is?
Answer & explanation
Correct answer: option 4
ATQ,
⇒ 50% A - 40% B = 4 ..........(i)
⇒ 70% A - 60% B = 2 ..........(ii)
(i) × 3 and (ii) × 2 and subtract, we get
⇒ 150% A - 120% B = 12
⇒ -140% A + 120% B = -4
⇒ 10% A = 8
⇒ A = 80
Value of A putting in equation (i)
⇒ 50% × 80 - 40% B = 4
⇒ \(\frac{1}{2}\) × 80 - \(\frac{2}{5}\) B = 4
⇒ 40 - \(\frac{2}{5}\)B = 4
⇒ \(\frac{2}{5}\)B = 36
⇒ B = 36 × \(\frac{5}{2}\)
⇒ B = 90
⇒ Hence the number is (A + B) = 80 + 90 = 170