There are the batting average of 40 innings of a player was 50 runs. His highest score exceed by lowest score by 172 runs. If this two innings are excluded, the average of 38 innings becomes 48 runs. Find the higher score of the player.
Answer & explanation
Correct answer: option 4
Innings Average Total Runs
40 × 50 = 2000
38 × 48 = 1824 ← excluding two innings
Runs of two innings = 176
Difference of two innings = 172
Let, lowest score = 172 + x
2x + 172 = 176
x = 2
Highest score = 172 + 2 = 174