There are the batting average of 40 innings of a player was 50 runs. His highest score exceed by lowest score by 172 runs. If this two innings are excluded, the average of 38 innings becomes 48 runs. Find the higher score of the player.

174

Innings      Average       Total Runs

   40     ×       50       =      2000

   38     ×       48       =      1824    ←  excluding two innings

Runs of two innings = 176

Difference of two innings = 172

Let, lowest score = 172 + x

2x + 172 = 176

x = 2

Highest score = 172 + 2 = 174