Masses of three wires of copper are in the ratio of 1 : 3 : 5 and their lengths are in the ratio of 5 : 3 : 1. The ratio of their electrical resistance are:

125 : 15 : 1

The correct answer is Option (4) → 125 : 15 : 1

Resistance (R) of a wire is

$R=ρ\frac{L}{A}=ρ\frac{L^2}{V}$   $A=\frac{V}{L}$

$R=\frac{ρdL^2}{M}$ [D = Density, $d =\frac{mass}{volume}$]

and, density of all the copper is same.

$∴R_1:R_2:R_3=\frac{5^2}{1}:\frac{3^2}{3}:\frac{1^2}{5}$

$=125:15:1$