A voltage of V = 10 Cos 10πt V flows through a resistor of 20 \(\Omega \). What will be the RMS current flowing through it?
Answer & explanation
Correct answer: option 4
I = \(\frac{V}{R}\) = \(\frac{10 Cos 10πt V}{20 \Omega }\) = 0.2 Cos 10πt A
Irms = 0.636Io = 0.636 x 0.2 A = 0.13 A