\(\int \frac{\log x}{x^{2}}dx\) is equal to
Answer & explanation
Correct answer: option 2
\(\int \frac{\log x}{x^{2}}dx=\frac{-\log x}{x}+\int\frac{1}{x^2}dx\)
$=\frac{-\log x}{x}-\frac{1}{x}+C$
$=-\frac{1}{x}(\log x+1)+C$
\(\int \frac{\log x}{x^{2}}dx\) is equal to
Correct answer: option 2
\(\int \frac{\log x}{x^{2}}dx=\frac{-\log x}{x}+\int\frac{1}{x^2}dx\)
$=\frac{-\log x}{x}-\frac{1}{x}+C$
$=-\frac{1}{x}(\log x+1)+C$