Practicing Success
The radius of hydrogen atom in its ground state is $5.3 \times 10^{-11}$ m. After collision with an electron it is found to have a radius of $21.2 \times 10^{-11}$ m. What is the principal quantum number n of the final state of the atom. |
n = 4 n = 2 n = 16 n = 3 |
n = 2 |
$r \propto n^2 \text { i.e. } \frac{r_f}{r_i}=\left(\frac{n_f}{n_i}\right)^2$ $\Rightarrow \frac{21.2 \times 10^{-11}}{5.3 \times 10^{-11}}=\left(\frac{n}{1}\right)^2 \Rightarrow n^2=4 \Rightarrow n=2$ |