The equation of the plane through the point (1. 4. -2) and parallel to the plane $-2x + y - 3z = 7, $ is
Answer & explanation
Correct answer: option 2
Let the equation of a plane parallel to the plane $-2x + y -3z = 7 $ be
$-2x + y -3z + k = 0 $ ..........(i)
This passes through $(1, 4, -2).$
$∴ (-2) (1) + 4 -3 (-2) + k = 0 ⇒ k = - 8 $
Putting $k = - 8$ in (i), we obtain
$-2x + y -3z - 8 = 0 ⇒ 2x- y + 3z + 8 = 0 $