If A and B are two independent events are such that P(A)= 0.3 and P(B…

Given that P(A)= 0.3 and P(B) = 0.6 

We know that, P(A and not B) = P(A ∩ B′)

                                            = P(A) - P(A ∩ B)

Since A and B are two independent events so,

P(A and B) = P(A ∩ B) = P(A). P(B)

                                 = 0.3 x0.6

                                 = 0.18

Hence, P(A and not B) = P(A ∩ B′) = 0.3 - 0.18

                                                   = 0.12