Practicing Success
If A and B are two independent events are such that P(A)= 0.3 and P(B) = 0.6 then find P(A and not B). |
0.18 0.21 0.12 0.14 |
0.12 |
Given that P(A)= 0.3 and P(B) = 0.6 We know that, P(A and not B) = P(A ∩ B′) = P(A) - P(A ∩ B) Since A and B are two independent events so, P(A and B) = P(A ∩ B) = P(A). P(B) = 0.3 x0.6 = 0.18 Hence, P(A and not B) = P(A ∩ B′) = 0.3 - 0.18 = 0.12 |