Read the row of digits below from left to right.
2 7 1 6 0 0 8 4 8 5 1 4 9 5 0 4 9 5 3 4 1 1 4 9 0
Take every three neighbouring digits of the row as a group (1st to 3rd, 2nd to 4th, 3rd to 5th, and so on). In how many of these groups is each digit greater than the digit before it?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 3
A group counts only when its three digits rise from left to right (first < second < third). Going from left to right, the groups that count are:
1, 4, 9 (11th to 13th digits)
0, 4, 9 (15th to 17th digits)
1, 4, 9 (22nd to 24th digits)
Every other group has a digit that is not greater than the one before it.
So the answer is 3.