The oxidation number of \(Co\) in complex \([Co(NH_2-CH_2-CH_2-NH_2)_3]_2(SO_4)_3\)
Answer & explanation
Correct answer: option 1
The correct answer is option 1. 3.
The given compound is \([Co(NH_2-CH_2-CH_2-NH_2)_3]_2(SO_4)_3\)
Let the oxidation number of \(Co\) in the given complex be \(x\)
The charge of \(NH_2-CH_2-CH_2-NH_2)\) ligand is \(0\)
The charge of \(SO_4\) is \(-2\)
\(∴ 2 × (x + 2 × 0) + 3(-2) = 0\)
or, \(2x + 0 - 6 = 0\)
or, \(2x = 6\)
or, \(x = 3\)
Thus, the oxidation number of \(Co\) is +3.