Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

Options:

a

b

c

d

Correct Answer:

d

Explanation:

$\omega = 2\pi f = 1500\pi$

$ \text{Impedance z } = \sqrt{R^2 + (\omega L - \frac{1}{\omega C})^2} = 834 \Omega$

$ I_{rms} = \frac{V_{rms}}{Z} =  \frac{20}{834} = 0.024 A$

$\text{Power Factor} cos\phi = \frac{R}{Z} = \frac{100}{834}$

$\text{Power }P = V_{rms} I_{rms} cos\phi = 20\times 0.024 \times \frac{100}{834} = 0.058J/s $ 

$ Time = \frac{20}{0.058} = 348 Sec$