Two equal sums are lent at 10% and 8% respectively at the same time. The first sum is received 2 years earlier than the second one and the amount received in each was Rs. 37800. Find sum.

21000

P + \(\frac{P × 10 × t}{100}\) = P + \(\frac{P × 8 (t+2)}{100}\)

10t = 8t +16

t = 8

total rate = 10% × 8 = 80%; P = 100%

A = 180% = 37800

1% = \(\frac{37800}{180}\)

P =100% =  \(\frac{37800}{180}\) × 100 = 21000