Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If tanθ - cotθ = 0°,   0° < θ < 90°

then, find the value of sin2θ + sec2θ.

Options:

\(\frac{5}{2}\)

2

\(\frac{4}{3}\)

\(\frac{7}{2}\)

Correct Answer:

\(\frac{5}{2}\)

Explanation:

tanθ - cotθ = 0° (only possible when tanθ = cotθ)

So, the θ must be 45°.

So,

sin2θ + sec2θ = (\(\frac{1}{\sqrt {2}}\))2+(\(\sqrt {2}\))2

= \(\frac{1}{2}\) + 2 = \(\frac{5}{2}\)