Practicing Success
If tanθ - cotθ = 0°, 0° < θ < 90° then, find the value of sin2θ + sec2θ. |
\(\frac{5}{2}\) 2 \(\frac{4}{3}\) \(\frac{7}{2}\) |
\(\frac{5}{2}\) |
tanθ - cotθ = 0° (only possible when tanθ = cotθ) So, the θ must be 45°. So, sin2θ + sec2θ = (\(\frac{1}{\sqrt {2}}\))2+(\(\sqrt {2}\))2 = \(\frac{1}{2}\) + 2 = \(\frac{5}{2}\) |