The photon energy, in eV, for electromagnetic waves of wavelength 40 m is
Answer & explanation
Correct answer: option 1
E = $h c / \lambda=\frac{6.63 \times 10^{-34} \times 3 \times 10^8}{40 \times e}$ = 3.1 × 10−8 ev
The photon energy, in eV, for electromagnetic waves of wavelength 40 m is
Correct answer: option 1
E = $h c / \lambda=\frac{6.63 \times 10^{-34} \times 3 \times 10^8}{40 \times e}$ = 3.1 × 10−8 ev