The following graph represents the $T-V$ curves of an ideal gas (where $T$ is the temperature and $V$ the volume) at three pressures $P_1, P_2$ and $P_3$ compared with those of Charles's law represented as dotted lines.

Then the correct relation is :

$P_1> P_2> P_3$

The correct answer is option (4) : $P_1> P_2> P_3$

At same temperature, curve with higher volume corresponds to lower pressure.

 $V_3> V_2> V_1$

$⇒P_1> P_2> P_3$

(We draw a straight line parallel to volume axis to get this)