Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(II), (B)-(III), (C)-(IV), (D)-(I) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) (A)-(IV), (B)-(III), (C)-(I), (D)-(II) (A)-(I), (B)-(II), (C)-(III), (D)-(IV) |
(A)-(II), (B)-(III), (C)-(IV), (D)-(I) |
The correct answer is Option (1) → (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
(A) $\hat{i} \cdot (\hat{j} \times \hat{k})$: $\hat{j} \times \hat{k} = \hat{i}$, so $\hat{i} \cdot \hat{i} = 1$ → (II) (B) $\hat{j} \cdot (\hat{i} \times \hat{k})$: $\hat{i} \times \hat{k} = -\hat{j}$, so $\hat{j} \cdot (-\hat{j}) = -1$ → (III) (C) $\hat{i} \times (\hat{j} \times \hat{k})$: $\hat{j} \times \hat{k} = \hat{i}$, so $\hat{i} \times \hat{i} = \vec{0}$ → (IV) (D) $\hat{j} \times \hat{i} = -\hat{k}$ → (I) |