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If $Δ=\begin{bmatrix}0 & b-a & c-a\\a-b & 0 & c-b\\ a-c & b-c & 0\end{bmatrix},$ then Δ equals |
$a+b+c$ $-(a+b+c)$ $abc$ 0 |
0 |
The correct answer is option (4) : 0 Clearly, Δ is the determinant of the skew-symmetric matrix A pf odd number where $A=\begin{bmatrix}0 & b-a & c-a\\a-b & 0 & c-b\\ a-c & b-c & 0\end{bmatrix}$ $∴Δ=|A|= 0 $ |
