
Answer & explanation
Correct answer: option 3
$\text{Intensity at a point where phase difference is }\Delta \phi \text{is given as } I = 4I_0 cos^2\frac{\Delta \phi}{2} = 2I_0, \Rightarrow cos\frac{\Delta \phi}{2} = \frac{1}{\sqrt 2}$
$\Rightarrow \frac{\Delta \phi}{2}= \frac{\pi}{4}, \Rightarrow \Delta\phi = \frac{\pi}{2}$
$\text{Path difference is }\Delta x = \frac{\lambda}{4} = (\mu -1)t$
$\Rightarrow t = \frac{\lambda /4}{(3/2 -1)} = \frac{\lambda}{2}$