$y=e^{\log _e\left(\sin ^{-1} x+\cos ^{-1} x\right)}$, then $\frac{d y}{d x}$ is
Answer & explanation
Correct answer: option 3
$y=e^{\log _e\left(\sin ^{-1} x+\cos ^{-1} x\right)}=\sin ^{-1} x+\cos ^{-1} x=\frac{\pi}{2} \Rightarrow \frac{d y}{d x}=0$
Hence (3) is correct answer.