CUET Preparation Today
In a binomial distribution, the probability of getting a success is $\frac{1}{3}$ and the standard deviation is 2. Then its mean is : |
12 8 24 6 |
6 |
$p=\frac{1}{3},\;q=\frac{2}{3}.$ $\text{Standard deviation }=\sqrt{npq}=2.$ $npq=4.$ $n\cdot\frac{2}{9}=4.$ $n=18.$ $\text{Mean }=np=18\cdot\frac{1}{3}=6.$ $\text{Mean }=6.$ |
