If $(a - 1)^2 + (b + 2)^2 + (c -1)^2 = 0, $ then the value of $a^2 + b^2 + c^2 $ is :
Answer & explanation
Correct answer: option 1
If $(a - 1)^2 + (b + 2)^2 + (c -1)^2 = 0, $ then
⇒ a - 1 = 0
a = 1
b + 2 = 0
⇒ b = -2
⇒ c - 1 = 0
c = 1
Put these values in the required equation,
$a^2 + b^2 + c^2 $ = 1^2 + -2^2 + 1^2
$a^2 + b^2 + c^2 $ = 6