If $(a - 1)^2 + (b + 2)^2 + (c -1)^2 = 0, $ then the value of $a^2 + b^2 + c^2 $ is :

6 0 2 1

6

If $(a - 1)^2 + (b + 2)^2 + (c -1)^2 = 0, $ then ⇒ a - 1 = 0 a = 1 b + 2 = 0 ⇒ b = -2 ⇒ c - 1 = 0 c = 1 Put these values in the required equation, $a^2 + b^2 + c^2 $ = 1^2 + -2^2 + 1^2 $a^2 + b^2 + c^2 $ = 6