Practicing Success
A hollow charged metal sphere has a radius R. If the potential difference between its surface and a point distant 3R from it center is V, then the electric field at a distance 3R from its center is |
$\frac{V}{6R}$ $\frac{V}{4R}$ $\frac{V}{3R}$ $\frac{V}{2R}$ |
$\frac{V}{6R}$ |
$ V = \frac{kQ}{R} - \frac{kQ}{3R} = \frac{2kQ}{3R}$ $ \text{Electric Field at 3R is } E = \frac{kQ}{9R^2} = \frac{V}{6R}$ |