Practicing Success
Practicing Success
CUET Preparation Today
If \(\vec{a}\) is a nonzero vector of magnitude \(a\) and \(\lambda\) is a nonzero scalar, then \(\lambda \vec{a}\) is unit vector if |
\(\lambda=1\) \(\lambda=-1\) \(a=\left|\lambda\right|\) \(a=\frac{1}{\left|\lambda \right|}\) |
\(a=\frac{1}{\left|\lambda \right|}\) |
| \(\begin{aligned}|\lambda \vec{a}|&=1\\ |\lambda ||\vec{a}|&=1\\ |\vec{a}|&=\frac{1}{|\lambda|}\end{aligned}\) |
