Practicing Success
Practicing Success
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Torque needed to deflect a magnet through $ 45^o$ in the earths horizontal magnetic field of induction $0.5\times 10^{-4}T$ is (Given the magnetic moment of magnet is$ 4A-m^2$) |
$14.1 \times 10^{-4} N-m$ $1.41 \times 10^{-4} N-m$ $2.4 \times 10^{-4} N-m$ $2 \times 10^{-4} N-m$ |
$1.41 \times 10^{-4} N-m$ |
$ \tau = \vec{M} \times \vec{B} = MBsin45^o = 4 \times 0.5 \times 10^{-4} \times \frac{1}{\sqrt 2} = 1.41\times 10^{-4}$ |
