A discrete random variable X has the following probability distribution: X 1 2 3 4 5 6 P(X) $\frac{2}{k}$ $\frac{4}{k}$ $\frac{1}{k}$ $\frac{2}{k}$ $\frac{3}{k}$ $\frac{5}{k}$ The value of k is :

$\frac{2}{17}$ 17 5 $\frac{1}{17}$

17