A discrete random variable X has the fol

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Target Exam

CUET

Subject

Applied Maths. Section B2

Chapter

Probability Distributions

Question:

A discrete random variable X has the following probability distribution:

X	1	2	3	4	5	6
P(X)	$\frac{2}{k}$	$\frac{4}{k}$	$\frac{1}{k}$	$\frac{2}{k}$	$\frac{3}{k}$	$\frac{5}{k}$

The value of k is :

Options:

$\frac{2}{17}$

$\frac{1}{17}$

Correct Answer:

Explanation:

The correct answer is Option (2) → 17

Sum of all probabilities must be 1.

$2/k+4/k+1/k+2/k+3/k+5/k=1$

$17/k=1$

k = 17