A discrete random variable X has the following probability distribution:
| X | 1 | 2 | 3 | 4 | 5 | 6 |
| P(X) | $\frac{2}{k}$ | $\frac{4}{k}$ | $\frac{1}{k}$ | $\frac{2}{k}$ | $\frac{3}{k}$ | $\frac{5}{k}$ |
The value of k is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 17
Sum of all probabilities must be 1.
$2/k+4/k+1/k+2/k+3/k+5/k=1$
$17/k=1$
k = 17