A lift is moving down with an acceleration a. A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift, and a man standing stationary on the ground are, respectively, :
Answer & explanation
Correct answer: option 2
\(\vec{a}_{b,l} = \vec{a}_b - \vec{a}_l\)
= \((g - a) \downarrow\)
\(\Rightarrow \vec{a}_b = g \downarrow\)