Practicing Success
If A and B are two sets, then $(A-B)∪(B-A)∪(A∩B)$ is equal to |
$A∪B$ $A∩B$ A B' |
$A∪B$ |
The correct answer is Option (1) → $A∪B$ It is evident from the Venn-diagram that $(A-B)∪(B-A)=(A∪B)-(A∩B)$ $∴((A-B)∪(B-A))∪(A∩B)$ $=((A∪B) -(A∩B))∪(A∩B) = A∪B$ |