The de Broglie wavelength is given by : λ=h/p where p is the momentum of the particle. For which of the following the de Broglie wavelength will be the least?
Answer & explanation
Correct answer: option 4
alpha particle.
λ=h/p=h/mv
⇒ λ∝1/m
∴ larger the mass, lesser the de Broglie wavelength.