If $x = \frac{1}{x} = 7, $ then $x^3 +\frac{1}{x^3}$ is equal to :
Answer & explanation
Correct answer: option 1
We know that,
If x + \(\frac{1}{x}\) = n
then, $x^3 +\frac{1}{x^3}$ = n3 - 3 × n
If $x = \frac{1}{x} = 7, $
then $x^3 +\frac{1}{x^3}$ = 73 - 3 × 7 = 343 - 21 = 322