In what ratio must a grocer mix two varieties of pulses worth ₹85 per kg and ₹100 per kg respectively so as to get a mixture worth ₹92 per jg ? |
8 : 7 8 : 9 6 : 7 7 : 8 |
8 : 7 |
The correct answer is option (1) : 8 : 7 Given c= ₹85 per kg. d= ₹100 per kg. m = ₹12 per kg. So, $\frac{\text{quantity of cheaper pulse}}{\text{quantity of dearer pulse}}$ $=\frac{100-92}{92-85}=\frac{8}{7}$ Hence the required ratio is $8 : 7$ |