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CUET
-- Mathematics - Section B1
Determinants
Evaluate $\begin{vmatrix} 2 & 4 \\ -1 & 2 \end{vmatrix}$.
0
4
8
-8
The correct answer is Option (3) → 8 ##
We have $\begin{vmatrix} 2 & 4 \\ -1 & 2 \end{vmatrix} = 2(2) - 4(-1)$
$= 4 + 4 = 8.$
