The programming problem
Max Z = 2x + 3y subject to the conditions $0 \leq x \leq 3,0 \leq y \leq 4$ is :
Answer & explanation
Correct answer: option 3
Objective f → Z = 2x + 3y
constraints :
0 ≤ x ≤ 3
0 ≤ y ≤ 4
| Corner point | Z(x, y) = 2x + 3y | |
| (0, 0) | Z(0, 0) = 0 + 0 = 0 (Zmin) | |
| (3, 0) | Z(3, 0) = 6 + 0 = 6 | |
| (0, 4) | Z(0, 4) = 0 + 12 = 12 | |
| (3, 4) | Z(3, 4) = 6 + 12 = 18 (Zmax) |