Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Determinants

Question:

The programming problem

Max Z = 2x + 3y subject to the conditions $0 \leq x \leq 3,0 \leq y \leq 4$ is :

Options:

not an LPP

an LPP, with unbounded feasible region and no solution

an LPP, and Max Z = 18, at x = 3, y = 4

an LPP, and Max Z = 12, at x = 0, y = 4

Correct Answer:

an LPP, and Max Z = 18, at x = 3, y = 4

Explanation:

Objective f → Z = 2x + 3y

constraints : 

0 ≤ x ≤ 3

0 ≤ y ≤ 4

 Corner point        Z(x, y) = 2x + 3y
 (0, 0)    Z(0, 0) = 0 + 0 = 0   (Zmin)
 (3, 0)    Z(3, 0) = 6 + 0 = 6
 (0, 4)    Z(0, 4) = 0 + 12 = 12
 (3, 4)    Z(3, 4) = 6 + 12 = 18  (Zmax)