A charged particle with charge q enters a region of constant, uniform and mutually orthogonal fields E and B with a velocity v perpendicular to both E and B, and comes out without any change in magnitude or direction of v. Then
Answer & explanation
Correct answer: option 1
As v of charged particle is remaining constant, it means force acting on charged particle is zero.
So, q(v × B) = qE
⇒ v × B = E
⇒ v $= \frac{E×B}{B^2}$