If a relation R is defined on the set Z of integers as follows: $(a, b) ∈R⇔a^2+b^2 = 25$. Then, Domain (R) =

{3, 4, 5} {0, 3, 4, 5} {0, ±3, ±4, ±5} none of these

{0, ±3, ±4, ±5}

The correct answer is Option (3) → {0, ±3, ±4, ±5} We have, $(a, b)∈R⇔a^2+b^2 = 25⇔b=±\sqrt{25-a^2}$ Clearly, $a = 0 ⇒ b=±5, a=±3 ⇒ b=±4$ $a=±4 ⇒b = ±3$ and, $a = ±5⇒ b=±0$ Hence, domain (R) = $\{a: (a, b) ∈ R\} = \{0,±3, ±4, ±5\}$.