Practicing Success
If A and B are square matrices such that $B=-A^{-1} BA$, then $(A + B)^2 =$ |
$O$ $A^2+ B^2$ $A^2+2AB+ B^2$ $A+B$ |
$A^2+ B^2$ |
We have, $B=-A^{-1} BA$ $⇒ AB=-A (A^{-1} BA)$ $⇒ AB=-((AA^{-1}) (BA))$ $⇒ AB=-(I (BA))$ $⇒ AB=-BA$ $⇒AB+ BA=0$ Now, $(A + B)^2 = (A + B) (A + B)$ $⇒(A + B)^2 =A^2 + AB + BA + B^2$ $⇒(A + B)^2 =A^2 +O+ B^2$ $⇒(A + B)^2 =A^2+ B^2$ |