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CUET
General Test
Quantitative Reasoning
Trigonometry
Find the value of \(\frac{sin\;θ . cosec\;θ tan\;θ cot\;θ}{sin^2θ + cos^2θ}\)
tanθ
0
2
1
\(\frac{sin\;θ . cosec\;θ. tan\;θ. cot\;θ}{sin^2θ + cos^2θ}\)
= 1 (because sinθ.cosecθ = 1), so tanθ.cotθ = 1 ⇒ sin2θ + cos2θ = 1