Find the value of \(\frac{sin\;θ . cosec\;θ tan\;θ cot\;θ}{sin^2θ + cos^2θ}\)
Answer & explanation
Correct answer: option 4
\(\frac{sin\;θ . cosec\;θ. tan\;θ. cot\;θ}{sin^2θ + cos^2θ}\)
= 1 (because sinθ.cosecθ = 1), so tanθ.cotθ = 1 ⇒ sin2θ + cos2θ = 1