$f(x)=\left\{\begin{matrix}-1:&x<-1\\-x:&-1≤x≤1\\1:&x>1\end{matrix}\right.$. Then f (x) at x = 0:
Answer & explanation
Correct answer: option 1
So, f (x) is continuous and differentiable at x = 0
$f(x)=\left\{\begin{matrix}-1:&x<-1\\-x:&-1≤x≤1\\1:&x>1\end{matrix}\right.$. Then f (x) at x = 0:
Correct answer: option 1
So, f (x) is continuous and differentiable at x = 0