CUET Preparation Today
$f(x)=\left\{\begin{matrix}-1:&x<-1\\-x:&-1≤x≤1\\1:&x>1\end{matrix}\right.$. Then f (x) at x = 0: |
is continuous is discontinuous is non-differentiable None of these |
is continuous |
So, f (x) is continuous and differentiable at x = 0 |
