Average of 49 numbers is 0. How many maximum possible numbers of above 0?

0 49 48 52

48

For being the average of 49 numbers to be zero, it is necessary that the sum of all numbers should be zero. let the sum of 48 numbers is x, Now it is necessary that the 49th number should be -x. Max - 48 numbers be greater than zero and 49th term will be opposite sign of sum of 48 terms.