Practicing Success
A, B and C are three numbers such that $A+B=10, B+C=19$ and $C+A=21,$ then number A, B and C respectively are |
4, 6, 17 4, 8, 11 6, 4, 15 8, 2, 17 |
6, 4, 15 |
We have, $A+B=10, B+C=19$ and $C+A=21,$ Note, no need to solve this question, Instead of solving this fully we can go through options for saving our time. The correct answer is option (3) : 6, 4, 15 |