The value of the integral $\int\limits_{-1}^1|x| dx$ is :

2 $\frac{1}{2}$ 1 0

1

$I = \int\limits_{-1}^1|x| dx$ |x| is even function $\int\limits_{-a}^a f(x) dx = 2\int\limits_{0}^a f(x) dx$ if f(x) is even $I = 2 \int\limits_{0}^1|x| dx$ $= 2 \int\limits_{0}^1|x| dx$ as |x| = x  in (0, 1) $=2\left[\frac{x^2}{2}\right]_0^1$ = 1 sq. units