If $A=\begin{bmatrix} -1 & 2 & 3\end{bmatrix}, B = \begin{bmatrix}3 \\2\\2\end{bmatrix}, C= \begin{bmatrix} 1 & 2 & 3\end{bmatrix} $ and $D= \begin{bmatrix}2 \\3\\4\end{bmatrix}$ then $AB+CD $ is equal to :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → [27]
$AB=\begin{bmatrix} -1 & 2 & 3\end{bmatrix}\begin{bmatrix}3 \\2\\2\end{bmatrix}=[-3+4+6]=[7]$
$CD= \begin{bmatrix} 1 & 2 & 3\end{bmatrix}\begin{bmatrix}2 \\3\\4\end{bmatrix}=[2+6+12]=[20]$
$AB+CD=[27]$