A series LCR circuit with an inductor, a capacitor and a resistor of resistance 50 Ω is connected to an ac source of 24 V, 50 Hz. The impedance of the circuit is 56 Ω. The average power dissipated in the circuit is

9.18 W

The correct answer is Option (1) → 9.18 W

Given: $R = 50\ \Omega,\ Z = 56\ \Omega,\ V = 24\ \text{V}$

RMS current: $I = \frac{V}{Z} = \frac{24}{56} = \frac{3}{7}\ \text{A}$

Average power dissipated: $P = I^{2} R = \left(\frac{3}{7}\right)^{2} \cdot 50 = \frac{9}{49} \cdot 50 = \frac{450}{49}\ \text{W}$

$P \approx 9.18\ \text{W}$

Answer: 9.2 W (approx.)