A chord of length 24 cm is at a distance of 5 cm from the centre of a circle. What is its area?

531.14 cm²

We know that,

(Hypotnuese)² = (perpendicular)² + base²

Area of circle = πR² 

According to the question,

Length of the chord = 24 cm 

In ΔOAC, OA = radius of triangle 

AC = \(\frac{1}{2}\) (AB) [we know that, chord is divide in equal part by perpendicular from center to the chord]

= OA² = (AC)² + (OC)² 

= OA = √(12² + 5²) = 13

Area of circle = πR² = (\(\frac{22}{7}\) ) × 13²

Area of circle = 531.14 cm²