A chord of length 24 cm is at a distance of 5 cm from the centre of a circle. What is its area?
Answer & explanation
Correct answer: option 3
We know that,
(Hypotnuese)2 = (perpendicular)2 + base2
Area of circle = πR2
According to the question,
Length of the chord = 24 cm
In ΔOAC, OA = radius of triangle
AC = \(\frac{1}{2}\) (AB) [we know that, chord is divide in equal part by perpendicular from center to the chord]
= OA2 = (AC)2 + (OC)2
= OA = √(122 + 52) = 13
Area of circle = πR2 = (\(\frac{22}{7}\) ) × 132
Area of circle = 531.14 cm2