Find the largest number which will divide 410, 751 and 1030 and leaves the remainder 7 in each case.
Answer & explanation
Correct answer: option 3
To find the largest number that divides 410, 751, 1030 and leaves 7 remainder, we subtract 7 from each number, so they're perfectly divisible.
⇒ 403, 744, 1023
Using elimination method from options : 25, 45 can be eliminated, because these numbers can not divide the above numbers.
Now check other two,
\(\frac{403}{31}\) , \(\frac{403}{23}\)
We can check, 31 is the only number which divides all numbers.
Therefore,
Ans. c) 31