Practicing Success
Eight mercury droplets having a radius of 1 mm and a charge of 0.066 pC each merge to form one droplet. Its potential is |
1.2V 2.4V 3V 4.8V |
2.4V |
Since Volume remains constant so Initial volume = Final Volume $ 8\times \frac{4\pi}{3} r^3 = \frac{4\pi}{3}R^3$ $ \Rightarrow R = 2r = 2mm ( r = 1mm)$ Since charge also remain constant . it is same on both the drops. $ \Rightarrow V = \frac{Q}{4\pi \epsilon_0 R} = \frac{9\times 10^9 \times 8\times 0.066\times 10^{-12}}{2\times 10^{-3}} = 2.4 V$
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